Reaction of(C6H5)(3)PbCl with 1 equiv of (THF)(2.5)LiGe(SiMe(3))(3) in ether afforded (C6H5)(3)PbGe(SiMe(3))(3) in 25% yield. An attempt to prepare (C6H5)(2)Pb(Ge(SiMe(3))(3))(2) by the reaction of 2 equiv of (THF)(2.5)LiGe(SiMe(3))(3) with Ph(2)PbCl(2) gave a mixture of the expected product as a yellow solid and a red-orange solid identified as the diplumbane, [(C6H5)(2)Pb (Ge(SiMe(3))(3)](2). The mono- and diplumbanes were separated by fractional crystallization from pentane and characterized by their elemental analyses, NMR spectra (H-1 and C-13) and infrared and UV-visible spectra. An X-ray structure determination on [(C6H5)(2)Pb(Ge(SiMe(3))(3)](2) was not completed due to decomposition of the crystal but showed it to be isomorphous with [(C6H5)(2)Pb(Si(SiMe(3))(3)](2), which is known to have a Pb-Pb bond. A low temperature X-ray structure determination on (C6H5)(2)Pb(Ge(SiMe(3))(3))(2) revealed it to be orthorhombic, Pnn2, with a = 13.999(5) Angstrom, b = 17.443(5) Angstrom, c = 10.404(2), V = 2541 Angstrom(3), and Z = 2. The molecular structure exhibited marked distortion of the coordination geometry around Pb with angle Ge-Pb-Ge = 135.0(1)degrees and angle C-Pb-C = 99.8(7)degrees. NMR studies of the two products found that the monoplumbane was stable for 20 h in ether but that the diplumbane experienced marked decomposition, during the same period.